Answer A is incorrect since no LOM is shown on the given chart. Answer B is incorrect because you would not squawk 7700 unless an emergency existed.
LessonName
PWI05.mpg
At 2,000 feet above the surface wind speed is greater than at the surface and tends to flow parallel the isobars. Surface winds tend to cross the isobars at an angle toward lower pressure and are weaker. Winds aloft tend to veer to the right of the surface winds.
The moment the TO FROM indicator becomes blank.
Station passage of a VOR occurs with the first positive, complete reversal of the TO-FROM indicator.
Land at the nearest airport that has VFR conditions.
PWI06.mpg
and 6
Coriolis force deflects the winds aloft so that they rotate clockwise around a high pressure system and counterclockwise around a low pressure system. The winds aloft move parallel to the isobars. Surface friction causes the winds near the surface to be slower and, therefore, less affected by Coriolis force. Surface friction causes the surface winds to flow across the isobars at an angle rather than parallel to the isobars.
Which force, in the Northern Hemisphere, acts at a right angle to the wind and deflects it to the right until parallel to the isobars?
Continue the flight at assigned altitude and route, start approach at your ETA, or, if late, start approach upon arrival.
PWI03.mpg
Course sensitivity of a VOR receiver may be checked by noting the number of degrees of change in the course selected as you rotate the OBS to move the CDI from center to the last dot on either side. This range should be between 10
and 12
The first movement of the CDI as the airplane enters the zone of confusion.
QuestionStem
SectionName
sectionsPerSubjectArea
and 12
SubjectAreaName
AnswerChoice
the flight by the most direct route to the fix specified in the last clearance.
Answer A is incorrect because the winds at 2,000 feet and the surface winds do not flow in the same direction, but it is true that surface winds are weaker. Answer C is incorrect because winds aloft veer to the right, not the surface winds.
Answers A and B are incorrect because the range is between 10
and 12
Answer A is incorrect because the reaction force described in Newton's third law, for every action there is an equal and opposite reaction is known as centrifugal force. Answer B is incorrect because pressure gradient tends to cause the wind to flow perpendicular to the isobars.
Squawk 7600. Since you have received an "expect approach clearance" for 1015, plan to begin your approach at 1015.
PWI02.mpg
PWI04.mpg
If the communications failure occurs during an IFR flight in VFR conditions, or if VFR conditions are encountered after the failure, the pilot shall continue the flight under VFR and land as soon as practicable. If the failure occurs under IFR conditions you would continue the flight at the assigned altitude and route and complete the approach. FAR 91.185.
The surface winds tend to veer to the right of the winds at 2,000 feet and are usually weaker.
Which procedure should you follow if, during an IFR flight in VFR conditions, you have two way radio communications failure?
The greater density of the air at the surface.
and 10
questionsPerSection
correctAns
When using VOR for navigation, which of the following should be considered as station passage?
Squawk 7600; plan to begin your approach at 1015.
lessonsPerSection
PWI08.mpg
What causes surface winds to flow across the isobars at an angle rather than parallel to the isobars?
FigNumber
Answer B is incorrect because continued flight at the assigned altitude may take you back into IFR conditions. Answer C is incorrect because it is not required to land at the nearest airport that has VFR conditions.
Answer A is incorrect because Coriolis force deflects the winds aloft so that they rotate clockwise around a high pressure system and counterclockwise around a low pressure system. The winds aloft move parallel to the isobars. Answer C is incorrect because greater density of the air at the surface does not influence whether surface winds will or will not flow across the isobars at an angle rather than parallel to the isobars.
videoFileName
FAA000.mpg
The winds at 2,000 feet tend to parallel the isobars while the surface winds cross the isobars at an angle toward lower pressure and are weaker.
PWI07.mpg
Coriolis.
A VOR receiver with normal five-dot course sensitivity shows a three-dot deflection at 30 NM from the station. The aircraft would be displaced approximately how far from the course centerline?
If the failure occurs in VFR conditions, or if VFR conditions are encountered after the failure, the pilot shall continue the flight under VFR, if possible, and land as soon as practicable. FAR 91.185.
Answer A is incorrect because if failure occurs in IFR conditions the pilot would continue on the route assigned in the last ATC clearance. Answer C is incorrect because the most direct route to the next fix may be through a mountain or restricted area.
Answers A and B are incorrect because neither the first movement of the CDI nor the TO-FROM indicator becoming blank as the VOR is approached is considered station passage.
Continue the flight under VFR and land as soon as practicable.
Pressure gradient.
QuestName
The winds at 2,000 feet and the surface winds flow in the same direction, but the surface winds are weaker due to friction.
Coriolis force.
(Refer to figure 87.) While holding at the 10 DME fix east of LCH for an ILS approach to RWY 15 at Lake Charles Regional airport, ATC advises you to expect clearance for the approach at 1015. At 1000 you experience two-way radio communications failure. Which procedure should be followed?
Squawk 7700 for 1 minute, then 7600. After 1 minute, descend to the minimum final approach fix altitude. Start your approach at 1015.
Coriolis force affects the paths of aircraft, ocean currents, and most important to the study of weather, air currents. Coriolis force deflects wind to the right in the Northern Hemisphere until the wind becomes parallel to the isobars.
Commclse.mpg
The first positive, complete reversal of the TO FROM indicator.
commopen.mpg
A full-scale 5-dot deflection would also be a 10
course change. A 3-dot deflection would be a 6
course change. If you are 60 NM from a VOR, 1
deflection equals one mile off course, or 6
deflection would be 6 miles off course. If you are only 30 NM from the VOR (half of 60 NM), then 6
of deflection would be half of 6 miles, or 3 NM off centerline.
Answers A and C are incorrect but could be obtained through faulty analysis or calculation.
When checking the sensitivity of a VOR receiver, the number of degrees in course change as the OBS is rotated to move the CDI from center to the last dot on either side should be between
cdNumber
In the event of two-way radio communications failure while operating on an IFR clearance in VFR conditions the pilot should continue
5 NM.
by the route assigned in the last ATC clearance received.
the flight under VFR and land as soon as practical.
Squawk 7600 and listen on the LOM frequency for instructions from ATC. If no instructions are received, start your approach at 1015.
Centrifugal.
Surface friction.
2 NM.
PWI01.mpg
What relationship exists between the winds at 2,000 feet above the surface and the surface winds?
3 NM.
initIVCPWIArrays
-- This routine creates Arrays
the IVC Instrument Rating Program
initIVCPWIArrays
4STRING SubjectAreaName[]
ectionName[][]
-LessonName[][][]
CQuestName[][][]
XvideoFileName[]
4INT subjectAreaCount
currentSectionNumber
/currentSectionCount
HcurrentLessonCount
`currentSubjectAreaNo
zcurrentLessonNumber
ectionsPerSubjectArea[]
lessonsPerSection[][]
QNO[][][][]
cdNumber[][][]
questionsPerSection[]
FigNumber[][][][]
"FAA000.mpg"
"PWI01.
"PWI02.
"PWI03.
"PWI04.
"PWI05.
"PWI06.
"PWI07.
"PWI08.
QuestionStem[][][][]
AnswerChoice[][][][][]
correctAns[][][][]
expl[][][][]
1][1][1]
1][1][2]
1][1][3]
1][1][4]
1][1][5]
1][1][6]
1][1][7]
[1] = 3 -- Set
[2] = 3 --
[3] = 3 --
1][1][1][1] = 4465
1][1][1][2] = 4500
1][1][1][3] = 4505
1][1][1][1] = "Which procedure should you follow
, during
IFR flight
)have two way radio communications failure?"
--- 4465
1][1][1][2] = "(Refer
figure 87.) While holding
10 DME fix east
ILS approach
RWY 15
)Lake Charles Regional airport, ATC advises
expect clearance
)1015. At 1000
experience
be followed?"
--4500
1][1][1][3] = "In
event
coperating on
pilot
--4505
1][1][2][1] = 4549
1][1][2][2] = 4551
1][1][2][3] = 4552
1][1][2][1] = "When
]VOR
navigation, which
following
be considered
%station passage?" --4549
1][1][2][2] = "
jchecking
sensitivity
receiver,
degrees
course change
rotated
Jdot on either
be between" --4551
1][1][2][3] = "A
wfive-
shows a three-
]deflection
)30 NM
. The aircraft would be displaced approximately
V far
enterline?" --4552
1][1][3][1] = 4105
1][1][3][2] = 4107
1][1][3][3] = 4108
1][1][3][1] = "What causes surface winds
flow across
isobars
angle rather than parallel
(?" --4105
1][1][3][2] = "
rrelationship exists
)2,000 feet above
?" --4107
1][1][3][3] = "
force,
> Northern Hemisphere, acts
deflects
?" --4108
1][1][1][2] = "87"
--4500
--4465
1][1][1][1][1] = "Continue
under
land
%soon
%practicable."
1][1][1][1][2] = "
)assigned altitude
route,
)your ETA,
late,
upon arrival."
1][1][1][1][3] = "Land
nearest
that has
--4500
1][1][1][2][1] = "Squawk 7600
listen on
LOM frequency
instructions
ATC. If no
received,
)1015."
1][1][1][2][2] = "
v700
1 minute,
F7600. After 1
descend
minimum final
. Start
)1015."
1][1][1][2][3] = "
; plan
begin
)1015."
--4505
. 1][1][1][3][1] = "
c 1][1][1][3][2] = "
%practical."
1][1][1][3][3] = "
most direct
specified
--4549
1][1][2][1][1] = "
movement
airplane enters
zone
confusion."
1][1][2][1][2] = "
moment
TO FROM indicator becomes blank."
1][1][2][1][3] = "
positive, complete reversal
--4551
1][1][2][2][1] = "5
1][1][2][2][2] = "8
1][1][2][2][3] = "10
--4552
1][1][2][3][1] = "2 NM."
1][1][2][3][2] = "3 NM."
1][1][2][3][3] = "5 NM."
--4105
1][1][3][1][1] = "Coriolis
1][1][3][1][2] = "Surface friction."
1][1][3][1][3] = "
greater density
--4107
1][1][3][2][1] = "
)2,000
same direction, but
are weaker due
1][1][3][2][2] = "
)2,000
tend
toward lower pressure
1][1][3][2][3] = "
veer
)2,000
usually
--4108
1][1][3][3][1] = "Centrifugal."
1][1][3][3][2] = "Pressure gradient."
1][1][3][3][3] = "
1][1][1][1] = "A" --4465
1][1][1][2] = "C" --4500
1][1][1][3] = "B" --4505
1][1][2][1] = "C" --4549
1][1][2][2] = "C" --4551
1][1][2][3] = "B" --4552
1][1][3][1] = "B" --4105
1][1][3][2] = "B" --4107
1][1][3][3] = "C" --4108
Expl[1][1][1][1] = " If
occurs
encountered
shall
. FAR 91.185." &
k& "
incorrect because continued
may take
xrequired
--- 4465
2] = "
. Since
1015,
)1015." &
k& "
since no
shown on
given chart.
xsquawk 7700 unless
emergency existed."
--- 4500
3] = " If
VFR,
possible,
k& "
be through a mountain
restricted area."
--- 4505
2][1] = " Station
." &
k& " Answers A
neither
ming
approached
--- 4549
2][2] = " Course
Hnoting
selected
." &
k& "
range
--- 4551
2][3] = " A full-scale 5-
also be a 10
. A 3-
. If
60 NM
a VOR, 1
equals
mile off
6 miles
. If
only 30 NM
(half
60 NM),
3 NM
jcenterline." &
k& "
ut could be obtained
faulty analysis
calculation."
--- 4552
3][1] = "
aloft so
they
clockwise around a high
counterclockwise
be slower
, therefore,
affected
." &
k& "
does
xinfluence whether
will
--- 4105
3][2] = " At 2,000
speed
tends
. Winds
." &
k& "
)2,000
--- 4107
3][3] = "
affects
paths
, ocean currents,
important
study
weather,
." &
k& "
reaction
described
Newton's
Glaw,
every
opposite
known
%centrifugal
perpendicular
--- 4108
"commopen.
"Commclse.
True
<BookPath>
:HDMEDIAPATH
Larry
info_LastSavedBy
9/6/2002 6:27:35 AM
info_LastSaved
System
Larry
Michael Ryan
9/6/2002 6:26:55 AM
ASYM_BeenHere
This System Book is used to initialize the Arrays for the SPV program.
9-06-026-02
Updated 11-15-2000
99021214371021441872157210520
ASYM_TpID
js-- This routine creates Arrays
the IVC Instrument Rating Program
initIVCPWIArrays
4STRING SubjectAreaName[]
ectionName[][]
-LessonName[][][]
CQuestName[][][]
XvideoFileName[]
4INT subjectAreaCount
currentSectionNumber
/currentSectionCount
HcurrentLessonCount
`currentSubjectAreaNo
zcurrentLessonNumber
ectionsPerSubjectArea[]
lessonsPerSection[][]
QNO[][][][]
cdNumber[][][]
questionsPerSection[]
FigNumber[][][][]
"FAA000.mpg"
"PWI01.
"PWI02.
"PWI03.
"PWI04.
"PWI05.
"PWI06.
"PWI07.
"PWI08.
QuestionStem[][][][]
AnswerChoice[][][][][]
correctAns[][][][]
expl[][][][]
1][1][1]
1][1][2]
1][1][3]
1][1][4]
1][1][5]
1][1][6]
1][1][7]
[1] = 3 -- Set
[2] = 3 --
[3] = 3 --
1][1][1][1] = 4465
1][1][1][2] = 4500
1][1][1][3] = 4505
1][1][1][1] = "Which procedure should you follow
, during
IFR flight
)have two way radio communications failure?"
--- 4465
1][1][1][2] = "(Refer
figure 87.) While holding
10 DME fix east
ILS approach
RWY 15
)Lake Charles Regional airport, ATC advises
expect clearance
)1015. At 1000
experience
be followed?"
--4500
1][1][1][3] = "In
event
coperating on
pilot
--4505
1][1][2][1] = 4549
1][1][2][2] = 4551
1][1][2][3] = 4552
1][1][2][1] = "When
]VOR
navigation, which
following
be considered
%station passage?" --4549
1][1][2][2] = "
jchecking
sensitivity
receiver,
degrees
course change
rotated
Jdot on either
be between" --4551
1][1][2][3] = "A
wfive-
shows a three-
]deflection
)30 NM
. The aircraft would be displaced approximately
V far
enterline?" --4552
1][1][3][1] = 4105
1][1][3][2] = 4107
1][1][3][3] = 4108
1][1][3][1] = "What causes surface winds
flow across
isobars
angle rather than parallel
(?" --4105
1][1][3][2] = "
rrelationship exists
)2,000 feet above
?" --4107
1][1][3][3] = "
force,
> Northern Hemisphere, acts
deflects
?" --4108
1][1][1][2] = "87"
--4500
--4465
1][1][1][1][1] = "Continue
under
land
%soon
%practicable."
1][1][1][1][2] = "
)assigned altitude
route,
)your ETA,
late,
upon arrival."
1][1][1][1][3] = "Land
nearest
that has
--4500
1][1][1][2][1] = "Squawk 7600
listen on
LOM frequency
instructions
ATC. If no
received,
)1015."
1][1][1][2][2] = "
v700
1 minute,
F7600. After 1
descend
minimum final
. Start
)1015."
1][1][1][2][3] = "
; plan
begin
)1015."
--4505
. 1][1][1][3][1] = "
c 1][1][1][3][2] = "
%practical."
1][1][1][3][3] = "
most direct
specified
--4549
1][1][2][1][1] = "
movement
airplane enters
zone
confusion."
1][1][2][1][2] = "
moment
TO FROM indicator becomes blank."
1][1][2][1][3] = "
positive, complete reversal
--4551
1][1][2][2][1] = "5
1][1][2][2][2] = "8
1][1][2][2][3] = "10
--4552
1][1][2][3][1] = "2 NM."
1][1][2][3][2] = "3 NM."
1][1][2][3][3] = "5 NM."
--4105
1][1][3][1][1] = "Coriolis
1][1][3][1][2] = "Surface friction."
1][1][3][1][3] = "
greater density
--4107
1][1][3][2][1] = "
)2,000
same direction, but
are weaker due
1][1][3][2][2] = "
)2,000
tend
toward lower pressure
1][1][3][2][3] = "
veer
)2,000
usually
--4108
1][1][3][3][1] = "Centrifugal."
1][1][3][3][2] = "Pressure gradient."
1][1][3][3][3] = "
1][1][1][1] = "A" --4465
1][1][1][2] = "C" --4500
1][1][1][3] = "B" --4505
1][1][2][1] = "C" --4549
1][1][2][2] = "C" --4551
1][1][2][3] = "B" --4552
1][1][3][1] = "B" --4105
1][1][3][2] = "B" --4107
1][1][3][3] = "C" --4108
Expl[1][1][1][1] = " If
occurs
encountered
shall
. FAR 91.185." &
k& "
incorrect because continued
may take
xrequired
--- 4465
2] = "
. Since
1015,
)1015." &
k& "
since no
shown on
given chart.
xsquawk 7700 unless
emergency existed."
--- 4500
3] = " If
VFR,
possible,
k& "
be through a mountain
restricted area."
--- 4505
2][1] = " Station
." &
k& " Answers A
neither
ming
approached
--- 4549
2][2] = " Course
Hnoting
selected
." &
k& "
range
--- 4551
2][3] = " A full-scale 5-
also be a 10
. A 3-
. If
60 NM
a VOR, 1
equals
mile off
6 miles
. If
only 30 NM
(half
60 NM),
3 NM
jcenterline." &
k& "
ut could be obtained
faulty analysis
calculation."
--- 4552
3][1] = "
aloft so
they
clockwise around a high
counterclockwise
be slower
, therefore,
affected
." &
k& "
does
xinfluence whether
will
--- 4105
3][2] = " At 2,000
speed
tends
. Winds
." &
k& "
)2,000
--- 4107
3][3] = "
affects
paths
, ocean currents,
important
study
weather,
." &
k& "
reaction
described
Newton's
Glaw,
every
opposite
known
%centrifugal
perpendicular
--- 4108
"commopen.
"Commclse.
True
-- This routine creates Arrays
the IVC Instrument Rating Program
initIVCSPVArrays
4STRING SubjectAreaName[]
ectionName[][]
-LessonName[][][]
CQuestName[][][]
XvideoFileName[]
4INT subjectAreaCount
currentSectionNumber
/currentSectionCount
HcurrentLessonCount
`currentSubjectAreaNo
zcurrentLessonNumber
ectionsPerSubjectArea[]
lessonsPerSection[][]
QNO[][][][]
cdNumber[][][]
questionsPerSection[]
FigNumber[][][][]
"FAA000.mpg"
"SPV01.
"SPV02.
"SPV03.
"SPV04.
"SPV05.
"SPV06.
"SPV07.
"SPV08.
QuestionStem[][][][]
AnswerChoice[][][][][]
correctAns[][][][]
expl[][][][]
1][1][1]
1][1][2]
1][1][3]
1][1][4]
1][1][5]
1][1][6]
1][1][7]
[1] = 3 -- Set
[2] = 3 --
[3] = 3 --
1][1][1][1] = 3639
1][1][1][2] = 3637
1][1][1][3] = 3640
1][1][1][1] = "What minimum altitude
necessary
vertically
obstacle on
northeast side
Airpark East Airport
H500 feet?"
--- 3639
1][1][1][2] = "
height
kapproximately 2 nautical miles southwest
Hampton-Varnville airport?"
-- 3637
1][1][1][3] = "You are approaching Garrison
)night.
obstacles within 5
H500
-- 3640
1][1][2][1] = 9977
1][1][2][2] = 9978
1][1][2][3] = 9979
1][1][2][1] = "When you see
sign
)a taxiway intersection
indicates that" -- 9977
1][1][2][2] = "
denotes" --9978
1][1][2][3] = "
xwould most likely be found" --9979
1][1][3][1] = 3117
1][1][3][2] = 3125
1][1][3][3] = 3599
1][1][3][1] = "A
^segmented
Uon a Sectional Chart depicts?" --3117
1][1][3][2] = "
radio equipment
required
operation
Class E airspace?" --3125
1][1][3][3] = "The
1 overlying Sulfur Springs
(SLR)
" --3599
1][1][1][1] = "25"
--3639
1][1][1][2] = "24"
--3637
1][1][1][3] = "22"
--3640
1][1][2][1] = "66"
--9977
1][1][2][2] = "66"
--9978
1][1][2][3] = "66"
--9979
1][1][3][3] = "25"
--3599
--3639
1][1][1][1][1] = "1,010
MSL."
1][1][1][1][2] = "1,273
1][1][1][1][3] = "1,283
--3637
1][1][1][2][1] = "351
AGL."
1][1][1][2][2] = "270
1][1][1][2][3] = "433
--3640
1][1][1][3][1] = "2,796
1][1][1][3][2] = "2,435
1][1][1][3][3] = "2,816
--9977
1][1][2][1][1] = "
1][1][2][1][2] = "
1][1][2][1][3] = "
--9978
1][1][2][2][1] = "intersecting taxiways."
1][1][2][2][2] = "
entrance
a runway
1][1][2][2][3] = "
area protected
aircraft
--9979
1][1][2][3][1] = "upon exiting
runways prior
calling ground control."
1][1][2][3][2] = "near
! 1][1][2][3][3] = "
where a roadway may be mistaken
--3117
| 1][1][3][1][1] = "
1][1][3][1][2] = "
1,200
1][1][3][1][3] = "
surface."
--3125
1][1][3][2][1] = "None."
1][1][3][2][2] = "Two-
communications
, a 4096-code transponder,
DME."
1][1][3][2][3] = "
, a 4096-
encoding altimeter."
--3599
1][1][3][3][1] = "
1][1][3][3][2] = "700
1][1][3][3][3] = "1,200
1][1][1][1] = "B" --3639
1][1][1][2] = "A" --3637
1][1][1][3] = "C" --3640
1][1][2][1] = "B" --9977
1][1][2][2] = "B" --9978
1][1][2][3] = "C" --9979
1][1][3][1] = "C" --3117
1][1][3][2] = "A" --3125
1][1][3][3] = "B" --3599
Expl[1][1][1][1] = "
." &
k& "
symbol
down
data block
%indicated
short
just
c. You'll find
elevation figure
5above
)773
f need
)1,273 (773+500)
MSL
H500
incorrect because 1,010 uses
t (510
) instead
than 500
t1,283
reflects adding
(510
--- 3639
2] = "
." &
k& " If
want
know
how tall
. So
always
level (AGL)
shown
parentheses below
7numerals
about 2
value
northwest
--- 3637
3] = "
." &
k& " There
three
; two
3 nm
4 nm
highest
fa peak
)2,316
. If
wanted
)least 500
, your
be 2,816
2,796
clears
H500
but
2,435
(1,935
MSL)
--- 3640
2][1] = "
." &
k& " A
5lettering
arrow
a direction
. In
, ""B"",
>points
telling
Taxiway Bravo goes
. AIM 2-3-10.
5B on
pointing
does
xgive
information
sA. Assuming
A exists,
could
%easily be
tells
a location
--- 9977
2][2] = "
." &
k& " A
holding
. It
used
MRunway 4-22.
enter
cross
have been cleared
tower,
)a non-
will
letters ""APCH""
B on
--- 9978
2][3] = "
." &
k& "
dcircle around a
. It
mark areas
entry
prohibited.
D marks
=. A
boundary
more
on a
. An
--- 9979
3][1] = "
." &
k& " A
Uon a
-based
starting
AGL
^vignette
700-foot
fuzzy
1,200
1,200-
--- 3117
3][2] = "
." &
k& " No
special
VFR operations
. However, even though
fall
such
B 30-NM
. FAR 91.130. Answers B
--- 3125
3][3] = "
." &
k& "
nd extension surrounding
starts
)700
began
be enclosed
)1,200
--- 3599
"commopen.
"Commclse.
True
--- 3599
"commopen.
"Commclse.
True
"commopen.
"Commclse.
True
perpendicular
--- 4108
"commopen.
"Commclse.
True
lessonsPerSection[][]
QNO[][][][]
cdNumber[][][]
questionsPerSection[]
FigNumber[][][][]
"FAA000.mpg"
"PWI01.
"PWI02.
"PWI03.
"PWI04.
"PWI05.
"PWI06.
"PWI07.
"PWI08.
QuestionStem[][][][]
AnswerChoice[][][][][]
correctAns[][][][]
expl[][][][]
1][1][1]
1][1][2]
1][1][3]
1][1][4]
1][1][5]
1][1][6]
1][1][7]
[1] = 3 -- Set
[2] = 3 --
[3] = 3 --
1][1][1][1] = 4465
1][1][1][2] = 4500
1][1][1][3] = 4505
1][1][1][1] = "Which procedure should you follow
, during
IFR flight
)have two way radio communications failure?"
--- 4465
1][1][1][2] = "(Refer
figure 87.) While holding
10 DME fix east
ILS approach
RWY 15
)Lake Charles Regional airport, ATC advises
expect clearance
)1015. At 1000
experience
be followed?"
--4500
1][1][1][3] = "In
event
coperating on
pilot
--4505
1][1][2][1] = 4549
1][1][2][2] = 4551
1][1][2][3] = 4552
1][1][2][1] = "When
]VOR
navigation, which
following
be considered
%station passage?" --4549
1][1][2][2] = "
jchecking
sensitivity
receiver,
degrees
course change
rotated
Jdot on either
be between" --4551
1][1][2][3] = "A
wfive-
shows a three-
]deflection
)30 NM
. The aircraft would be displaced approximately
V far
enterline?" --4552
1][1][3][1] = 4105
1][1][3][2] = 4107
1][1][3][3] = 4108
1][1][3][1] = "What causes surface winds
flow across
isobars
angle rather than parallel
(?" --4105
1][1][3][2] = "
rrelationship exists
)2,000 feet above
?" --4107
1][1][3][3] = "
force,
> Northern Hemisphere, acts
deflects
?" --4108
1][1][1][2] = "87"
--4500
--4465
1][1][1][1][1] = "Continue
under
land
%soon
%practicable."
1][1][1][1][2] = "
)assigned altitude
route,
)your ETA,
late,
upon arrival."
1][1][1][1][3] = "Land
nearest
that has
--4500
1][1][1][2][1] = "Squawk 7600
listen on
LOM frequency
instructions
ATC. If no
received,
)1015."
1][1][1][2][2] = "
v700
1 minute,
F7600. After 1
descend
minimum final
. Start
)1015."
1][1][1][2][3] = "
; plan
begin
)1015."
--4505
. 1][1][1][3][1] = "
c 1][1][1][3][2] = "
1][1][1][3][3] = "
most direct
specified
--4549
1][1][2][1][1] = "
movement
airplane enters
zone
confusion."
1][1][2][1][2] = "
moment
TO FROM indicator becomes blank."
1][1][2][1][3] = "
positive, complete reversal
--4551
1][1][2][2][1] = "5
1][1][2][2][2] = "8
1][1][2][2][3] = "10
--4552
1][1][2][3][1] = "2 NM."
1][1][2][3][2] = "3 NM."
1][1][2][3][3] = "5 NM."
--4105
1][1][3][1][1] = "Coriolis
1][1][3][1][2] = "Surface friction."
1][1][3][1][3] = "
greater density
--4107
1][1][3][2][1] = "
)2,000
same direction, but
are weaker due
1][1][3][2][2] = "
)2,000
tend
toward lower pressure
1][1][3][2][3] = "
veer
)2,000
usually
--4108
1][1][3][3][1] = "Centrifugal."
1][1][3][3][2] = "Pressure gradient."
1][1][3][3][3] = "
1][1][1][1] = "A" --4465
1][1][1][2] = "C" --4500
1][1][1][3] = "B" --4505
1][1][2][1] = "C" --4549
1][1][2][2] = "C" --4551
1][1][2][3] = "B" --4552
1][1][3][1] = "B" --4105
1][1][3][2] = "B" --4107
1][1][3][3] = "C" --4108
Expl[1][1][1][1] = "
." &
k& " If
occurs
encountered
shall
. FAR 91.185." &
k& "
incorrect because continued
may take
xrequired
--- 4465
2] = "
." &
k& "
. Since
1015,
)1015." &
k& "
since no
shown on
given chart.
xsquawk 7700 unless
emergency existed."
--- 4500
3] = "
." &
k& " If
VFR,
possible,
k& "
be through a mountain
restricted area."
--- 4505
2][1] = "
." &
k& " Station
." &
k& " Answers A
neither
ming
approached
--- 4549
2][2] = "
." &
k& " Course
Hnoting
selected
." &
k& "
range
--- 4551
2][3] = "
." &
k& " A full-scale 5-
also be a 10
. A 3-
. If
60 NM
a VOR, 1
equals
mile off
6 miles
. If
only 30 NM
(half
60 NM),
3 NM
jcenterline." &
k& "
ut could be obtained
faulty analysis
calculation."
--- 4552
3][1] = "
." &
k& "
aloft so
they
clockwise around a high
counterclockwise
be slower
, therefore,
affected
." &
k& "
does
xinfluence whether
will
--- 4105
3][2] = "
." &
k& " At 2,000
speed
tends
. Winds
." &
k& "
)2,000
--- 4107
u 3][3] = "
." &
k& "
affects
paths
, ocean currents,
important
study
weather,
." &
k& "
reaction
described
Newton's
Glaw,
every
opposite
known
%centrifugal
perpendicular
--- 4108
"commopen.
"Commclse.
True
-- This routine creates Arrays
the IVC Instrument Rating Program
initIVCSPVArrays
4STRING SubjectAreaName[]
ectionName[][]
-LessonName[][][]
CQuestName[][][]
XvideoFileName[]
4INT subjectAreaCount
currentSectionNumber
/currentSectionCount
HcurrentLessonCount
`currentSubjectAreaNo
zcurrentLessonNumber
ectionsPerSubjectArea[]
lessonsPerSection[][]
QNO[][][][]
cdNumber[][][]
questionsPerSection[]
FigNumber[][][][]
"FAA000.mpg"
"SPV01.
"SPV02.
"SPV03.
"SPV04.
"SPV05.
"SPV06.
"SPV07.
"SPV08.
QuestionStem[][][][]
AnswerChoice[][][][][]
correctAns[][][][]
expl[][][][]
1][1][1]
1][1][2]
1][1][3]
1][1][4]
1][1][5]
1][1][6]
1][1][7]
[1] = 3 -- Set
[2] = 3 --
[3] = 3 --
1][1][1][1] = 3639
1][1][1][2] = 3637
1][1][1][3] = 3640
1][1][1][1] = "What minimum altitude
necessary
vertically
obstacle on
northeast side
Airpark East Airport
H500 feet?"
--- 3639
1][1][1][2] = "
height
kapproximately 2 nautical miles southwest
Hampton-Varnville airport?"
-- 3637
1][1][1][3] = "You are approaching Garrison
)night.
obstacles within 5
H500
-- 3640
1][1][2][1] = 9977
1][1][2][2] = 9978
1][1][2][3] = 9979
1][1][2][1] = "When you see
sign
)a taxiway intersection
indicates that" -- 9977
1][1][2][2] = "
denotes" --9978
1][1][2][3] = "
xwould most likely be found" --9979
1][1][3][1] = 3117
1][1][3][2] = 3125
1][1][3][3] = 3599
1][1][3][1] = "A
^segmented
Uon a Sectional Chart depicts?" --3117
1][1][3][2] = "
radio equipment
required
operation
Class E airspace?" --3125
1][1][3][3] = "The
1 overlying Sulfur Springs
(SLR)
" --3599
1][1][1][1] = "25"
--3639
1][1][1][2] = "24"
--3637
1][1][1][3] = "22"
--3640
1][1][2][1] = "66"
--9977
1][1][2][2] = "66"
--9978
1][1][2][3] = "66"
--9979
1][1][3][3] = "25"
--3599
--3639
1][1][1][1][1] = "1,010
MSL."
1][1][1][1][2] = "1,273
1][1][1][1][3] = "1,283
--3637
1][1][1][2][1] = "351
AGL."
1][1][1][2][2] = "270
1][1][1][2][3] = "433
--3640
1][1][1][3][1] = "2,796
1][1][1][3][2] = "2,435
1][1][1][3][3] = "2,816
--9977
1][1][2][1][1] = "
1][1][2][1][2] = "
1][1][2][1][3] = "
--9978
1][1][2][2][1] = "intersecting taxiways."
1][1][2][2][2] = "
entrance
a runway
1][1][2][2][3] = "
area protected
aircraft
--9979
1][1][2][3][1] = "upon exiting
runways prior
calling ground control."
1][1][2][3][2] = "near
! 1][1][2][3][3] = "
where a roadway may be mistaken
--3117
| 1][1][3][1][1] = "
1][1][3][1][2] = "
1,200
1][1][3][1][3] = "
surface."
--3125
1][1][3][2][1] = "None."
1][1][3][2][2] = "Two-
communications
, a 4096-code transponder,
DME."
1][1][3][2][3] = "
, a 4096-
encoding altimeter."
--3599
1][1][3][3][1] = "
1][1][3][3][2] = "700
1][1][3][3][3] = "1,200
1][1][1][1] = "B" --3639
1][1][1][2] = "A" --3637
1][1][1][3] = "C" --3640
1][1][2][1] = "B" --9977
1][1][2][2] = "B" --9978
1][1][2][3] = "C" --9979
1][1][3][1] = "C" --3117
1][1][3][2] = "A" --3125
1][1][3][3] = "B" --3599
Expl[1][1][1][1] = "
." &
k& "
symbol
down
data block
%indicated
short
just
c. You'll find
elevation figure
5above
)773
f need
)1,273 (773+500)
MSL
H500
incorrect because 1,010 uses
t (510
) instead
than 500
t1,283
reflects adding
(510
--- 3639
2] = "
." &
k& " If
want
know
how tall
. So
always
level (AGL)
shown
parentheses below
7numerals
about 2
value
northwest
--- 3637
3] = "
." &
k& " There
three
; two
3 nm
4 nm
highest
fa peak
)2,316
. If
wanted
)least 500
, your
be 2,816
2,796
clears
H500
but
2,435
(1,935
MSL)
--- 3640
2][1] = "
." &
k& " A
5lettering
arrow
a direction
. In
, ""B"",
>points
telling
Taxiway Bravo goes
. AIM 2-3-10.
5B on
pointing
does
xgive
information
sA. Assuming
A exists,
could
%easily be
tells
a location
--- 9977
2][2] = "
." &
k& " A
holding
. It
used
MRunway 4-22.
enter
cross
have been cleared
tower,
)a non-
will
letters ""APCH""
B on
--- 9978
2][3] = "
." &
k& "
dcircle around a
. It
mark areas
entry
prohibited.
D marks
=. A
boundary
more
on a
. An
--- 9979
3][1] = "
." &
k& " A
Uon a
-based
starting
AGL
^vignette
700-foot
fuzzy
1,200
1,200-
--- 3117
3][2] = "
." &
k& " No
special
VFR operations
. However, even though
fall
such
B 30-NM
. FAR 91.130. Answers B
--- 3125
3][3] = "
." &
k& "
nd extension surrounding
starts
)700
began
be enclosed
)1,200
--- 3599
"commopen.
"Commclse.
True
--- 3599
"commopen.
"Commclse.
True
"commopen.
"Commclse.
True
perpendicular
--- 4108
"commopen.
"Commclse.
True
Answer A is incorrect since no LOM is shown on the given chart. Answer B is incorrect because you would not squawk 7700 unless an emergency existed.
LessonName
PWI05.mpg
At 2,000 feet above the surface wind speed is greater than at the surface and tends to flow parallel the isobars. Surface winds tend to cross the isobars at an angle toward lower pressure and are weaker. Winds aloft tend to veer to the right of the surface winds.
The moment the TO FROM indicator becomes blank.
Station passage of a VOR occurs with the first positive, complete reversal of the TO-FROM indicator.
Land at the nearest airport that has VFR conditions.
PWI06.mpg
and 6
Coriolis force deflects the winds aloft so that they rotate clockwise around a high pressure system and counterclockwise around a low pressure system. The winds aloft move parallel to the isobars. Surface friction causes the winds near the surface to be slower and, therefore, less affected by Coriolis force. Surface friction causes the surface winds to flow across the isobars at an angle rather than parallel to the isobars.
Which force, in the Northern Hemisphere, acts at a right angle to the wind and deflects it to the right until parallel to the isobars?
Continue the flight at assigned altitude and route, start approach at your ETA, or, if late, start approach upon arrival.
PWI03.mpg
Course sensitivity of a VOR receiver may be checked by noting the number of degrees of change in the course selected as you rotate the OBS to move the CDI from center to the last dot on either side. This range should be between 10
and 12
The first movement of the CDI as the airplane enters the zone of confusion.
QuestionStem
SectionName
sectionsPerSubjectArea
and 12
SubjectAreaName
AnswerChoice
the flight by the most direct route to the fix specified in the last clearance.
Answer A is incorrect because the winds at 2,000 feet and the surface winds do not flow in the same direction, but it is true that surface winds are weaker. Answer C is incorrect because winds aloft veer to the right, not the surface winds.
Answers A and B are incorrect because the range is between 10
and 12
Answer A is incorrect because the reaction force described in Newton's third law, for every action there is an equal and opposite reaction is known as centrifugal force. Answer B is incorrect because pressure gradient tends to cause the wind to flow perpendicular to the isobars.
Squawk 7600. Since you have received an "expect approach clearance" for 1015, plan to begin your approach at 1015.
PWI02.mpg
PWI04.mpg
If the communications failure occurs during an IFR flight in VFR conditions, or if VFR conditions are encountered after the failure, the pilot shall continue the flight under VFR and land as soon as practicable. If the failure occurs under IFR conditions you would continue the flight at the assigned altitude and route and complete the approach. FAR 91.185.
The surface winds tend to veer to the right of the winds at 2,000 feet and are usually weaker.
Which procedure should you follow if, during an IFR flight in VFR conditions, you have two way radio communications failure?
The greater density of the air at the surface.
and 10
questionsPerSection
correctAns
When using VOR for navigation, which of the following should be considered as station passage?
Squawk 7600; plan to begin your approach at 1015.
lessonsPerSection
PWI08.mpg
What causes surface winds to flow across the isobars at an angle rather than parallel to the isobars?
FigNumber
Answer B is incorrect because continued flight at the assigned altitude may take you back into IFR conditions. Answer C is incorrect because it is not required to land at the nearest airport that has VFR conditions.
Answer A is incorrect because Coriolis force deflects the winds aloft so that they rotate clockwise around a high pressure system and counterclockwise around a low pressure system. The winds aloft move parallel to the isobars. Answer C is incorrect because greater density of the air at the surface does not influence whether surface winds will or will not flow across the isobars at an angle rather than parallel to the isobars.
videoFileName
FAA000.mpg
The winds at 2,000 feet tend to parallel the isobars while the surface winds cross the isobars at an angle toward lower pressure and are weaker.
PWI07.mpg
Coriolis.
A VOR receiver with normal five-dot course sensitivity shows a three-dot deflection at 30 NM from the station. The aircraft would be displaced approximately how far from the course centerline?
If the failure occurs in VFR conditions, or if VFR conditions are encountered after the failure, the pilot shall continue the flight under VFR, if possible, and land as soon as practicable. FAR 91.185.
Answer A is incorrect because if failure occurs in IFR conditions the pilot would continue on the route assigned in the last ATC clearance. Answer C is incorrect because the most direct route to the next fix may be through a mountain or restricted area.
Answers A and B are incorrect because neither the first movement of the CDI nor the TO-FROM indicator becoming blank as the VOR is approached is considered station passage.
Continue the flight under VFR and land as soon as practicable.
Pressure gradient.
QuestName
The winds at 2,000 feet and the surface winds flow in the same direction, but the surface winds are weaker due to friction.
Coriolis force.
(Refer to figure 87.) While holding at the 10 DME fix east of LCH for an ILS approach to RWY 15 at Lake Charles Regional airport, ATC advises you to expect clearance for the approach at 1015. At 1000 you experience two-way radio communications failure. Which procedure should be followed?
Squawk 7700 for 1 minute, then 7600. After 1 minute, descend to the minimum final approach fix altitude. Start your approach at 1015.
Coriolis force affects the paths of aircraft, ocean currents, and most important to the study of weather, air currents. Coriolis force deflects wind to the right in the Northern Hemisphere until the wind becomes parallel to the isobars.
Commclse.mpg
The first positive, complete reversal of the TO FROM indicator.
commopen.mpg
A full-scale 5-dot deflection would also be a 10
course change. A 3-dot deflection would be a 6
course change. If you are 60 NM from a VOR, 1
deflection equals one mile off course, or 6
deflection would be 6 miles off course. If you are only 30 NM from the VOR (half of 60 NM), then 6
of deflection would be half of 6 miles, or 3 NM off centerline.
Answers A and C are incorrect but could be obtained through faulty analysis or calculation.
When checking the sensitivity of a VOR receiver, the number of degrees in course change as the OBS is rotated to move the CDI from center to the last dot on either side should be between
cdNumber
In the event of two-way radio communications failure while operating on an IFR clearance in VFR conditions the pilot should continue
5 NM.
by the route assigned in the last ATC clearance received.
the flight under VFR and land as soon as practical.
Squawk 7600 and listen on the LOM frequency for instructions from ATC. If no instructions are received, start your approach at 1015.
Centrifugal.
Surface friction.
2 NM.
PWI01.mpg
What relationship exists between the winds at 2,000 feet above the surface and the surface winds?
3 NM.
initIVCPWIArrays
Class E airspace with a floor of 700 feet AGL.
2,435 feet MSL.
LessonName
cdNumber
SPV01.mpg
1,010 feet MSL.
Answer C is correct.
FigNumber
1,283 feet MSL.
an entrance to a runway from a taxiway.
Two-way radio communications equipment, a 4096-code transponder, and an encoding altimeter.
SPV05.mpg
SPV02.mpg
No radio communications or special equipment is required for VFR operations within Class E airspace. However, even though Class E airspace does not require radio or special equipment, it may fall within areas that do require a transponder and an encoding altimeter such as within a Class B 30-NM circle. FAR 91.130. Answers B and C are incorrect because Class E airspace does not require radio equipment.
upon exiting all runways prior to calling ground control.
1,273 feet MSL.
SPV06.mpg
When you see this sign, it denotes
QuestionStem
SectionName
SPV03.mpg
sectionsPerSubjectArea
SubjectAreaName
A magenta segmented (or dashed) line on a Sectional Chart depicts surface-based Class E airspace. Answer A is incorrect because Class E airspace starting at a floor of 700 feet AGL is shown with a magenta vignette boundary. The 700-foot Class E floor is on the fuzzy side of the magenta vignette boundary. Answer B is incorrect because Class E airspace starting at a floor of 1,200 feet AGL (not MSL) is shown with a blue vignette boundary. The 1,200-foot Class E floor is on the fuzzy side of the blue vignette boundary.
AnswerChoice
intersecting taxiways.
FAA000.mpg
you are on taxiway B.
If you want to know the height, you want to know how tall the obstacle is above the ground. So the height of an obstacle is always above ground level (AGL) and is shown in parentheses below the bold numerals that show the MSL elevation of the top. The 351 in parentheses is the height of the obstacle about 2 miles southwest of the of the Hampton-Varnville airport in feet AGL. Answer B is incorrect because 270 is the height value of the obstacle about 3 miles northwest of the Hampton-Varnville airport, and it's AGL not MSL. Answer C is incorrect because 433 is the MSL elevation, not the AGL height of the obstacle southwest of the Hampton-Varnville airport.
1,200 MSL.
This sign would most likely be found
A yellow sign with black lettering and an arrow is a direction sign. In this case the sign has the name of a taxiway, "B", and the arrow points to the right. This is a taxiway direction sign telling you that Taxiway Bravo goes to the right. AIM 2-3-10. Answer A is incorrect because a black B on yellow background sign with an arrow pointing to the right does not give you any information about Taxiway A. Assuming that Taxiway A exists, it could just as easily be to the right as to the left. Answer C is incorrect because a sign that tells you where you are is a location sign that has a black background and yellow lettering.
SPV04.mpg
questionsPerSection
correctAns
lessonsPerSection
The Airpark East airport symbol is to the left and down from the Airpark East data block as indicated with the short dotted line. The obstacle for this question is just north-northeast of the airport symbol. You'll find the elevation figure just above the obstacle symbol. The top of the obstacle is at 773 feet MSL. You would need to fly at 1,273 (773+500) feet MSL to vertically clear the obstacle by 500 feet. Answer A is incorrect because 1,010 uses the elevation of Airpark East Airport (510 feet) instead of the obstacle elevation of 773 feet and you would clear the obstacle by less than 500 feet. Answer C is incorrect because 1,283 feet reflects adding the airport elevation of Airpark East (510 feet) to the obstacle elevation of 773 feet.
What is the height of the obstacle approximately 2 nautical miles southwest of the Hampton-Varnville airport?
Class E airspace with a floor of 1,200 feet MSL.
Answer A is correct.
videoFileName
SPV08.mpg
at the surface.
A magenta segmented line on a Sectional Chart depicts?
Two-way radio communications equipment, a 4096-code transponder, and DME.
351 feet AGL.
Class E airspace at the surface.
SPV07.mpg
What minimum radio equipment is required for operation within Class E airspace?
QuestName
What minimum altitude is necessary to vertically clear the obstacle on the northeast side of Airpark East Airport by 500 feet?
You are approaching Garrison Airport from the west at night. What minimum altitude is necessary to vertically clear all obstacles within 5 nautical miles of the Garrison Airport by 500 feet?
A red sign with white numerals is a runway holding position sign. It is used to denote an entrance to a runway from a taxiway-in this case Runway 4-22. The runway holding position sign tells you not to enter or cross the runway until you have been cleared by the tower, or at a non-tower airport, until the runway is clear. AIM 2-3-8. Answer A is incorrect because you would see a yellow taxiway direction sign with a black taxiway letter and arrow at intersecting taxiways. Answer C is incorrect because the sign that denotes an area protected for aircraft on approach will have the runway number and the letters "APCH" as shown with sign B on figure 66.
433 feet AGL.
None.
commopen.mpg
taxiway A is to the left.
The floor of Class E airspace overlying Sulfur Springs airport (SLR) is
Answer B is correct.
700 feet AGL.
The floor of the Class E airspace overlying Sulfur Springs airport (SLR) is 700 feet AGL as indicated by the magenta vignette circle and extension surrounding it. The fuzzy side of the vignette boundary tells you where the airspace starts at 700 feet above the surface. Answer A is incorrect because if the Class E airspace began at the surface, the airport would be enclosed with a magenta dashed line. Answer C is incorrect because Class E with a floor at 1,200 feet AGL (not MSL) is shown with a blue vignette, not magenta.
The red sign with a white circle around a horizontal line would most likely be found at an intersection where a roadway may be mistaken as a taxiway. It is used to mark areas where the entry of aircraft is prohibited. Answer A is incorrect because sign D marks an aircraft prohibited area. A runway boundary sign (G) is more likely one to be found on a taxiway when exiting a runway. Answer B is incorrect because sign D marks an aircraft prohibited area. An ILS protected area sign (C) is more likely to found near the approach end of ILS runways.
Commclse.mpg
at an intersection where a roadway may be mistaken as a taxiway.
2,816 feet MSL.
270 feet MSL.
There are three obstacles within 5 nautical miles of Garrison airport; two within 3 nm to the northeast, and one approximately 4 nm to the west. The highest obstacle is the one to the west with a peak elevation at 2,316 feet. If you wanted to clear all the obstacles vertically by at least 500 feet, your minimum altitude would be 2,816 feet MSL. Answer A is incorrect because 2,796 feet MSL clears the obstacles to the northeast of Garrison airport by 500 feet but not the obstacle to the west. Answer B is incorrect because 2,435 feet MSL is 500 feet above the Garrison Airport elevation (1,935 feet MSL) not the obstacles.
an area protected for an aircraft approaching a runway.
When you see this sign at a taxiway intersection it indicates that
2,796 feet MSL.
taxiway B is to the right.
near the approach end of ILS runways.
initIVCSPVArrays
796 feet MSL.
taxiway B is to the right.
(Refer to figure 24, area 1.) What is the height of the obstacle approximately 2 nautical miles southwest of the Hampton-Varnville airport?
initIVCSPVArrays
face friction.
2 NM.
PWI01.mpg
What relationship exists between the winds at 2,000 feet above the surface and the surface winds?
3 NM.
initIVCPWIArrays
Answer A is incorrect since no LOM is shown on the given chart. Answer B is incorrect because you would not squawk 7700 unless an emergency existed.
the flight under VFR and land as soon as practicable.
LessonName
PWI05.mpg
Answer C is correct.
At 2,000 feet above the surface wind speed is greater than at the surface and tends to flow parallel the isobars. Surface winds tend to cross the isobars at an angle toward lower pressure and are weaker. Winds aloft tend to veer to the right of the surface winds.
The moment the TO FROM indicator becomes blank.
Station passage of a VOR occurs with the first positive, complete reversal of the TO-FROM indicator.
Land at the nearest airport that has VFR conditions.
PWI06.mpg
and 6
Coriolis force deflects the winds aloft so that they rotate clockwise around a high pressure system and counterclockwise around a low pressure system. The winds aloft move parallel to the isobars. Surface friction causes the winds near the surface to be slower and, therefore, less affected by Coriolis force. Surface friction causes the surface winds to flow across the isobars at an angle rather than parallel to the isobars.
Which force, in the Northern Hemisphere, acts at a right angle to the wind and deflects it to the right until parallel to the isobars?
Continue the flight at assigned altitude and route, start approach at your ETA, or, if late, start approach upon arrival.
PWI03.mpg
Course sensitivity of a VOR receiver may be checked by noting the number of degrees of change in the course selected as you rotate the OBS to move the CDI from center to the last dot on either side. This range should be between 10
and 12
The first movement of the CDI as the airplane enters the zone of confusion.
QuestionStem
SectionName
sectionsPerSubjectArea
and 12
SubjectAreaName
AnswerChoice
the flight by the most direct route to the fix specified in the last clearance.
Answer A is incorrect because the winds at 2,000 feet and the surface winds do not flow in the same direction, but it is true that surface winds are weaker. Answer C is incorrect because winds aloft veer to the right, not the surface winds.
Answers A and B are incorrect because the range is between 10
and 12
Answer A is incorrect because the reaction force described in Newton's third law, for every action there is an equal and opposite reaction is known as centrifugal force. Answer B is incorrect because pressure gradient tends to cause the wind to flow perpendicular to the isobars.
Squawk 7600. Since you have received an "expect approach clearance" for 1015, plan to begin your approach at 1015.
PWI02.mpg
PWI04.mpg
If the communications failure occurs during an IFR flight in VFR conditions, or if VFR conditions are encountered after the failure, the pilot shall continue the flight under VFR and land as soon as practicable. If the failure occurs under IFR conditions you would continue the flight at the assigned altitude and route and complete the approach. FAR 91.185.
The surface winds tend to veer to the right of the winds at 2,000 feet and are usually weaker.
Which procedure should you follow if, during an IFR flight in VFR conditions, you have two way radio communications failure?
The greater density of the air at the surface.
and 10
questionsPerSection
correctAns
When using VOR for navigation, which of the following should be considered as station passage?
Squawk 7600; plan to begin your approach at 1015.
lessonsPerSection
PWI08.mpg
What causes surface winds to flow across the isobars at an angle rather than parallel to the isobars?
FigNumber
Answer B is incorrect because continued flight at the assigned altitude may take you back into IFR conditions. Answer C is incorrect because it is not required to land at the nearest airport that has VFR conditions.
Answer A is incorrect because Coriolis force deflects the winds aloft so that they rotate clockwise around a high pressure system and counterclockwise around a low pressure system. The winds aloft move parallel to the isobars. Answer C is incorrect because greater density of the air at the surface does not influence whether surface winds will or will not flow across the isobars at an angle rather than parallel to the isobars.
Answer A is correct.
videoFileName
FAA000.mpg
The winds at 2,000 feet tend to parallel the isobars while the surface winds cross the isobars at an angle toward lower pressure and are weaker.
PWI07.mpg
Coriolis.
A VOR receiver with normal five-dot course sensitivity shows a three-dot deflection at 30 NM from the station. The aircraft would be displaced approximately how far from the course centerline?
If the failure occurs in VFR conditions, or if VFR conditions are encountered after the failure, the pilot shall continue the flight under VFR, if possible, and land as soon as practicable. FAR 91.185.
Answer A is incorrect because if failure occurs in IFR conditions the pilot would continue on the route assigned in the last ATC clearance. Answer C is incorrect because the most direct route to the next fix may be through a mountain or restricted area.
Answers A and B are incorrect because neither the first movement of the CDI nor the TO-FROM indicator becoming blank as the VOR is approached is considered station passage.
Continue the flight under VFR and land as soon as practicable.
Pressure gradient.
QuestName
The winds at 2,000 feet and the surface winds flow in the same direction, but the surface winds are weaker due to friction.
Coriolis force.
(Refer to figure 87.) While holding at the 10 DME fix east of LCH for an ILS approach to RWY 15 at Lake Charles Regional airport, ATC advises you to expect clearance for the approach at 1015. At 1000 you experience two-way radio communications failure. Which procedure should be followed?
Squawk 7700 for 1 minute, then 7600. After 1 minute, descend to the minimum final approach fix altitude. Start your approach at 1015.
Coriolis force affects the paths of aircraft, ocean currents, and most important to the study of weather, air currents. Coriolis force deflects wind to the right in the Northern Hemisphere until the wind becomes parallel to the isobars.
The first positive, complete reversal of the TO FROM indicator.
commopen.mpg
A full-scale 5-dot deflection would also be a 10
course change. A 3-dot deflection would be a 6
course change. If you are 60 NM from a VOR, 1
deflection equals one mile off course, or 6
deflection would be 6 miles off course. If you are only 30 NM from the VOR (half of 60 NM), then 6
of deflection would be half of 6 miles, or 3 NM off centerline.
Answers A and C are incorrect but could be obtained through faulty analysis or calculation.
When checking the sensitivity of a VOR receiver, the number of degrees in course change as the OBS is rotated to move the CDI from center to the last dot on either side should be between
cdNumber
In the event of two-way radio communications failure while operating on an IFR clearance in VFR conditions the pilot should continue
5 NM.
Answer B is correct.
by the route assigned in the last ATC clearance received.
Commclse.mpg
Squawk 7600 and listen on the LOM frequency for instructions from ATC. If no instructions are received, start your approach at 1015.
Centrifugal.
Surface friction.
2 NM.
PWI01.mpg
What relationship exists between the winds at 2,000 feet above the surface and the surface winds?
3 NM.
initIVCPWIArrays
Class E airspace with a floor of 700 feet AGL.
2,435 feet MSL.
LessonName
cdNumber
SPV01.mpg
1,010 feet MSL.
Answer C is correct.
FigNumber
1,283 feet MSL.
an entrance to a runway from a taxiway.
Two-way radio communications equipment, a 4096-code transponder, and an encoding altimeter.
SPV05.mpg
SPV02.mpg
No radio communications or special equipment is required for VFR operations within Class E airspace. However, even though Class E airspace does not require radio or special equipment, it may fall within areas that do require a transponder and an encoding altimeter such as within a Class B 30-NM circle. FAR 91.130. Answers B and C are incorrect because Class E airspace does not require radio equipment.
upon exiting all runways prior to calling ground control.
1,273 feet MSL.
SPV06.mpg
When you see this sign, it denotes
QuestionStem
SectionName
SPV03.mpg
sectionsPerSubjectArea
SubjectAreaName
A magenta segmented (or dashed) line on a Sectional Chart depicts surface-based Class E airspace. Answer A is incorrect because Class E airspace starting at a floor of 700 feet AGL is shown with a magenta vignette boundary. The 700-foot Class E floor is on the fuzzy side of the magenta vignette boundary. Answer B is incorrect because Class E airspace starting at a floor of 1,200 feet AGL (not MSL) is shown with a blue vignette boundary. The 1,200-foot Class E floor is on the fuzzy side of the blue vignette boundary.
AnswerChoice
intersecting taxiways.
FAA000.mpg
you are on taxiway B.
If you want to know the height, you want to know how tall the obstacle is above the ground. So the height of an obstacle is always above ground level (AGL) and is shown in parentheses below the bold numerals that show the MSL elevation of the top. The 351 in parentheses is the height of the obstacle about 2 miles southwest of the of the Hampton-Varnville airport in feet AGL. Answer B is incorrect because 270 is the height value of the obstacle about 3 miles northwest of the Hampton-Varnville airport, and it's AGL not MSL. Answer C is incorrect because 433 is the MSL elevation, not the AGL height of the obstacle southwest of the Hampton-Varnville airport.
1,200 MSL.
This sign would most likely be found
A yellow sign with black lettering and an arrow is a direction sign. In this case the sign has the name of a taxiway, "B", and the arrow points to the right. This is a taxiway direction sign telling you that Taxiway Bravo goes to the right. AIM 2-3-10. Answer A is incorrect because a black B on yellow background sign with an arrow pointing to the right does not give you any information about Taxiway A. Assuming that Taxiway A exists, it could just as easily be to the right as to the left. Answer C is incorrect because a sign that tells you where you are is a location sign that has a black background and yellow lettering.
SPV04.mpg
questionsPerSection
correctAns
lessonsPerSection
The Airpark East airport symbol is to the left and down from the Airpark East data block as indicated with the short dotted line. The obstacle for this question is just north-northeast of the airport symbol. You'll find the elevation figure just above the obstacle symbol. The top of the obstacle is at 773 feet MSL. You would need to fly at 1,273 (773+500) feet MSL to vertically clear the obstacle by 500 feet. Answer A is incorrect because 1,010 uses the elevation of Airpark East Airport (510 feet) instead of the obstacle elevation of 773 feet and you would clear the obstacle by less than 500 feet. Answer C is incorrect because 1,283 feet reflects adding the airport elevation of Airpark East (510 feet) to the obstacle elevation of 773 feet.
What is the height of the obstacle approximately 2 nautical miles southwest of the Hampton-Varnville airport?
Class E airspace with a floor of 1,200 feet MSL.
Answer A is correct.
videoFileName
SPV08.mpg
at the surface.
A magenta segmented line on a Sectional Chart depicts?
Two-way radio communications equipment, a 4096-code transponder, and DME.
351 feet AGL.
Class E airspace at the surface.
SPV07.mpg
What minimum radio equipment is required for operation within Class E airspace?
QuestName
What minimum altitude is necessary to vertically clear the obstacle on the northeast side of Airpark East Airport by 500 feet?
You are approaching Garrison Airport from the west at night. What minimum altitude is necessary to vertically clear all obstacles within 5 nautical miles of the Garrison Airport by 500 feet?
A red sign with white numerals is a runway holding position sign. It is used to denote an entrance to a runway from a taxiway-in this case Runway 4-22. The runway holding position sign tells you not to enter or cross the runway until you have been cleared by the tower, or at a non-tower airport, until the runway is clear. AIM 2-3-8. Answer A is incorrect because you would see a yellow taxiway direction sign with a black taxiway letter and arrow at intersecting taxiways. Answer C is incorrect because the sign that denotes an area protected for aircraft on approach will have the runway number and the letters "APCH" as shown with sign B on figure 66.
433 feet AGL.
None.
commopen.mpg
taxiway A is to the left.
The floor of Class E airspace overlying Sulfur Springs airport (SLR) is
Answer B is correct.
700 feet AGL.
The floor of the Class E airspace overlying Sulfur Springs airport (SLR) is 700 feet AGL as indicated by the magenta vignette circle and extension surrounding it. The fuzzy side of the vignette boundary tells you where the airspace starts at 700 feet above the surface. Answer A is incorrect because if the Class E airspace began at the surface, the airport would be enclosed with a magenta dashed line. Answer C is incorrect because Class E with a floor at 1,200 feet AGL (not MSL) is shown with a blue vignette, not magenta.
The red sign with a white circle around a horizontal line would most likely be found at an intersection where a roadway may be mistaken as a taxiway. It is used to mark areas where the entry of aircraft is prohibited. Answer A is incorrect because sign D marks an aircraft prohibited area. A runway boundary sign (G) is more likely one to be found on a taxiway when exiting a runway. Answer B is incorrect because sign D marks an aircraft prohibited area. An ILS protected area sign (C) is more likely to found near the approach end of ILS runways.
Commclse.mpg
at an intersection where a roadway may be mistaken as a taxiway.
2,816 feet MSL.
270 feet MSL.
There are three obstacles within 5 nautical miles of Garrison airport; two within 3 nm to the northeast, and one approximately 4 nm to the west. The highest obstacle is the one to the west with a peak elevation at 2,316 feet. If you wanted to clear all the obstacles vertically by at least 500 feet, your minimum altitude would be 2,816 feet MSL. Answer A is incorrect because 2,796 feet MSL clears the obstacles to the northeast of Garrison airport by 500 feet but not the obstacle to the west. Answer B is incorrect because 2,435 feet MSL is 500 feet above the Garrison Airport elevation (1,935 feet MSL) not the obstacles.
an area protected for an aircraft approaching a runway.
When you see this sign at a taxiway intersection it indicates that
2,796 feet MSL.
taxiway B is to the right.
near the approach end of ILS runways.
initIVCSPVArrays
initIVCSPVArrays
e right.
(Refer to figure 24, area 1.) What is the height of the obstacle approximately 2 nautical miles southwest of the Hampton-Varnville airport?
initIVCSPVArrays
face friction.
2 NM.
PWI01.mpg
What relationship exists between the winds at 2,000 feet above the surface and the surface winds?
3 NM.
initIVCPWIArrays
Answer A is incorrect since no LOM is shown on the given chart. Answer B is incorrect because you would not squawk 7700 unless an emergency existed.
the flight under VFR and land as soon as practicable.
LessonName
PWI05.mpg
At 2,000 feet above the surface wind speed is greater than at the surface and tends to flow parallel the isobars. Surface winds tend to cross the isobars at an angle toward lower pressure and are weaker. Winds aloft tend to veer to the right of the surface winds.
The moment the TO FROM indicator becomes blank.
Station passage of a VOR occurs with the first positive, complete reversal of the TO-FROM indicator.
Land at the nearest airport that has VFR conditions.
PWI06.mpg
and 6
Coriolis force deflects the winds aloft so that they rotate clockwise around a high pressure system and counterclockwise around a low pressure system. The winds aloft move parallel to the isobars. Surface friction causes the winds near the surface to be slower and, therefore, less affected by Coriolis force. Surface friction causes the surface winds to flow across the isobars at an angle rather than parallel to the isobars.
Which force, in the Northern Hemisphere, acts at a right angle to the wind and deflects it to the right until parallel to the isobars?
Continue the flight at assigned altitude and route, start approach at your ETA, or, if late, start approach upon arrival.
PWI03.mpg
Course sensitivity of a VOR receiver may be checked by noting the number of degrees of change in the course selected as you rotate the OBS to move the CDI from center to the last dot on either side. This range should be between 10
and 12
The first movement of the CDI as the airplane enters the zone of confusion.
QuestionStem
SectionName
sectionsPerSubjectArea
and 12
SubjectAreaName
AnswerChoice
the flight by the most direct route to the fix specified in the last clearance.
Answer A is incorrect because the winds at 2,000 feet and the surface winds do not flow in the same direction, but it is true that surface winds are weaker. Answer C is incorrect because winds aloft veer to the right, not the surface winds.
Answers A and B are incorrect because the range is between 10
and 12
Answer A is incorrect because the reaction force described in Newton's third law, for every action there is an equal and opposite reaction is known as centrifugal force. Answer B is incorrect because pressure gradient tends to cause the wind to flow perpendicular to the isobars.
Squawk 7600. Since you have received an "expect approach clearance" for 1015, plan to begin your approach at 1015.
PWI02.mpg
PWI04.mpg
If the communications failure occurs during an IFR flight in VFR conditions, or if VFR conditions are encountered after the failure, the pilot shall continue the flight under VFR and land as soon as practicable. If the failure occurs under IFR conditions you would continue the flight at the assigned altitude and route and complete the approach. FAR 91.185.
The surface winds tend to veer to the right of the winds at 2,000 feet and are usually weaker.
Which procedure should you follow if, during an IFR flight in VFR conditions, you have two way radio communications failure?
The greater density of the air at the surface.
and 10
questionsPerSection
correctAns
When using VOR for navigation, which of the following should be considered as station passage?
Squawk 7600; plan to begin your approach at 1015.
lessonsPerSection
PWI08.mpg
What causes surface winds to flow across the isobars at an angle rather than parallel to the isobars?
FigNumber
Answer B is incorrect because continued flight at the assigned altitude may take you back into IFR conditions. Answer C is incorrect because it is not required to land at the nearest airport that has VFR conditions.
Answer A is incorrect because Coriolis force deflects the winds aloft so that they rotate clockwise around a high pressure system and counterclockwise around a low pressure system. The winds aloft move parallel to the isobars. Answer C is incorrect because greater density of the air at the surface does not influence whether surface winds will or will not flow across the isobars at an angle rather than parallel to the isobars.
videoFileName
FAA000.mpg
The winds at 2,000 feet tend to parallel the isobars while the surface winds cross the isobars at an angle toward lower pressure and are weaker.
PWI07.mpg
Coriolis.
A VOR receiver with normal five-dot course sensitivity shows a three-dot deflection at 30 NM from the station. The aircraft would be displaced approximately how far from the course centerline?
If the failure occurs in VFR conditions, or if VFR conditions are encountered after the failure, the pilot shall continue the flight under VFR, if possible, and land as soon as practicable. FAR 91.185.
Answer A is incorrect because if failure occurs in IFR conditions the pilot would continue on the route assigned in the last ATC clearance. Answer C is incorrect because the most direct route to the next fix may be through a mountain or restricted area.
Answers A and B are incorrect because neither the first movement of the CDI nor the TO-FROM indicator becoming blank as the VOR is approached is considered station passage.
Continue the flight under VFR and land as soon as practicable.
Pressure gradient.
QuestName
The winds at 2,000 feet and the surface winds flow in the same direction, but the surface winds are weaker due to friction.
Coriolis force.
(Refer to figure 87.) While holding at the 10 DME fix east of LCH for an ILS approach to RWY 15 at Lake Charles Regional airport, ATC advises you to expect clearance for the approach at 1015. At 1000 you experience two-way radio communications failure. Which procedure should be followed?
Squawk 7700 for 1 minute, then 7600. After 1 minute, descend to the minimum final approach fix altitude. Start your approach at 1015.
Coriolis force affects the paths of aircraft, ocean currents, and most important to the study of weather, air currents. Coriolis force deflects wind to the right in the Northern Hemisphere until the wind becomes parallel to the isobars.
The first positive, complete reversal of the TO FROM indicator.
commopen.mpg
A full-scale 5-dot deflection would also be a 10
course change. A 3-dot deflection would be a 6
course change. If you are 60 NM from a VOR, 1
deflection equals one mile off course, or 6
deflection would be 6 miles off course. If you are only 30 NM from the VOR (half of 60 NM), then 6
of deflection would be half of 6 miles, or 3 NM off centerline.
Answers A and C are incorrect but could be obtained through faulty analysis or calculation.
When checking the sensitivity of a VOR receiver, the number of degrees in course change as the OBS is rotated to move the CDI from center to the last dot on either side should be between
cdNumber
In the event of two-way radio communications failure while operating on an IFR clearance in VFR conditions the pilot should continue
5 NM.
by the route assigned in the last ATC clearance received.
Commclse.mpg
Squawk 7600 and listen on the LOM frequency for instructions from ATC. If no instructions are received, start your approach at 1015.
Centrifugal.
Surface friction.
2 NM.
PWI01.mpg
What relationship exists between the winds at 2,000 feet above the surface and the surface winds?
3 NM.
initIVCPWIArrays
Answer A is incorrect since no LOM is shown on the given chart. Answer B is incorrect because you would not squawk 7700 unless an emergency existed.
the flight under VFR and land as soon as practicable.
LessonName
PWI05.mpg
Answer C is correct.
At 2,000 feet above the surface wind speed is greater than at the surface and tends to flow parallel the isobars. Surface winds tend to cross the isobars at an angle toward lower pressure and are weaker. Winds aloft tend to veer to the right of the surface winds.
The moment the TO FROM indicator becomes blank.
Station passage of a VOR occurs with the first positive, complete reversal of the TO-FROM indicator.
Land at the nearest airport that has VFR conditions.
PWI06.mpg
and 6
Coriolis force deflects the winds aloft so that they rotate clockwise around a high pressure system and counterclockwise around a low pressure system. The winds aloft move parallel to the isobars. Surface friction causes the winds near the surface to be slower and, therefore, less affected by Coriolis force. Surface friction causes the surface winds to flow across the isobars at an angle rather than parallel to the isobars.
Which force, in the Northern Hemisphere, acts at a right angle to the wind and deflects it to the right until parallel to the isobars?
Continue the flight at assigned altitude and route, start approach at your ETA, or, if late, start approach upon arrival.
PWI03.mpg
Course sensitivity of a VOR receiver may be checked by noting the number of degrees of change in the course selected as you rotate the OBS to move the CDI from center to the last dot on either side. This range should be between 10
and 12
The first movement of the CDI as the airplane enters the zone of confusion.
QuestionStem
SectionName
sectionsPerSubjectArea
and 12
SubjectAreaName
AnswerChoice
the flight by the most direct route to the fix specified in the last clearance.
Answer A is incorrect because the winds at 2,000 feet and the surface winds do not flow in the same direction, but it is true that surface winds are weaker. Answer C is incorrect because winds aloft veer to the right, not the surface winds.
Answers A and B are incorrect because the range is between 10
and 12
Answer A is incorrect because the reaction force described in Newton's third law, for every action there is an equal and opposite reaction is known as centrifugal force. Answer B is incorrect because pressure gradient tends to cause the wind to flow perpendicular to the isobars.
Squawk 7600. Since you have received an "expect approach clearance" for 1015, plan to begin your approach at 1015.
PWI02.mpg
PWI04.mpg
If the communications failure occurs during an IFR flight in VFR conditions, or if VFR conditions are encountered after the failure, the pilot shall continue the flight under VFR and land as soon as practicable. If the failure occurs under IFR conditions you would continue the flight at the assigned altitude and route and complete the approach. FAR 91.185.
The surface winds tend to veer to the right of the winds at 2,000 feet and are usually weaker.
Which procedure should you follow if, during an IFR flight in VFR conditions, you have two way radio communications failure?
The greater density of the air at the surface.
and 10
questionsPerSection
correctAns
When using VOR for navigation, which of the following should be considered as station passage?
Squawk 7600; plan to begin your approach at 1015.
lessonsPerSection
PWI08.mpg
What causes surface winds to flow across the isobars at an angle rather than parallel to the isobars?
FigNumber
Answer B is incorrect because continued flight at the assigned altitude may take you back into IFR conditions. Answer C is incorrect because it is not required to land at the nearest airport that has VFR conditions.
Answer A is incorrect because Coriolis force deflects the winds aloft so that they rotate clockwise around a high pressure system and counterclockwise around a low pressure system. The winds aloft move parallel to the isobars. Answer C is incorrect because greater density of the air at the surface does not influence whether surface winds will or will not flow across the isobars at an angle rather than parallel to the isobars.
Answer A is correct.
videoFileName
FAA000.mpg
The winds at 2,000 feet tend to parallel the isobars while the surface winds cross the isobars at an angle toward lower pressure and are weaker.
PWI07.mpg
Coriolis.
A VOR receiver with normal five-dot course sensitivity shows a three-dot deflection at 30 NM from the station. The aircraft would be displaced approximately how far from the course centerline?
If the failure occurs in VFR conditions, or if VFR conditions are encountered after the failure, the pilot shall continue the flight under VFR, if possible, and land as soon as practicable. FAR 91.185.
Answer A is incorrect because if failure occurs in IFR conditions the pilot would continue on the route assigned in the last ATC clearance. Answer C is incorrect because the most direct route to the next fix may be through a mountain or restricted area.
Answers A and B are incorrect because neither the first movement of the CDI nor the TO-FROM indicator becoming blank as the VOR is approached is considered station passage.
Continue the flight under VFR and land as soon as practicable.
Pressure gradient.
QuestName
The winds at 2,000 feet and the surface winds flow in the same direction, but the surface winds are weaker due to friction.
Coriolis force.
(Refer to figure 87.) While holding at the 10 DME fix east of LCH for an ILS approach to RWY 15 at Lake Charles Regional airport, ATC advises you to expect clearance for the approach at 1015. At 1000 you experience two-way radio communications failure. Which procedure should be followed?
Squawk 7700 for 1 minute, then 7600. After 1 minute, descend to the minimum final approach fix altitude. Start your approach at 1015.
Coriolis force affects the paths of aircraft, ocean currents, and most important to the study of weather, air currents. Coriolis force deflects wind to the right in the Northern Hemisphere until the wind becomes parallel to the isobars.
The first positive, complete reversal of the TO FROM indicator.
commopen.mpg
A full-scale 5-dot deflection would also be a 10
course change. A 3-dot deflection would be a 6
course change. If you are 60 NM from a VOR, 1
deflection equals one mile off course, or 6
deflection would be 6 miles off course. If you are only 30 NM from the VOR (half of 60 NM), then 6
of deflection would be half of 6 miles, or 3 NM off centerline.
Answers A and C are incorrect but could be obtained through faulty analysis or calculation.
When checking the sensitivity of a VOR receiver, the number of degrees in course change as the OBS is rotated to move the CDI from center to the last dot on either side should be between
cdNumber
In the event of two-way radio communications failure while operating on an IFR clearance in VFR conditions the pilot should continue
5 NM.
Answer B is correct.
by the route assigned in the last ATC clearance received.
Commclse.mpg
Squawk 7600 and listen on the LOM frequency for instructions from ATC. If no instructions are received, start your approach at 1015.
Centrifugal.
Surface friction.
2 NM.
PWI01.mpg
What relationship exists between the winds at 2,000 feet above the surface and the surface winds?
3 NM.
initIVCPWIArrays
Answer A is incorrect since no LOM is shown on the given chart. Answer B is incorrect because you would not squawk 7700 unless an emergency existed.
the flight under VFR and land as soon as practicable.
LessonName
PWI05.mpg
Answer C is correct.
At 2,000 feet above the surface wind speed is greater than at the surface and tends to flow parallel the isobars. Surface winds tend to cross the isobars at an angle toward lower pressure and are weaker. Winds aloft tend to veer to the right of the surface winds.
The moment the TO FROM indicator becomes blank.
Station passage of a VOR occurs with the first positive, complete reversal of the TO-FROM indicator.
Land at the nearest airport that has VFR conditions.
PWI06.mpg
and 6
Coriolis force deflects the winds aloft so that they rotate clockwise around a high pressure system and counterclockwise around a low pressure system. The winds aloft move parallel to the isobars. Surface friction causes the winds near the surface to be slower and, therefore, less affected by Coriolis force. Surface friction causes the surface winds to flow across the isobars at an angle rather than parallel to the isobars.
Which force, in the Northern Hemisphere, acts at a right angle to the wind and deflects it to the right until parallel to the isobars?
Continue the flight at assigned altitude and route, start approach at your ETA, or, if late, start approach upon arrival.
PWI03.mpg
Course sensitivity of a VOR receiver may be checked by noting the number of degrees of change in the course selected as you rotate the OBS to move the CDI from center to the last dot on either side. This range should be between 10
and 12
The first movement of the CDI as the airplane enters the zone of confusion.
QuestionStem
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sectionsPerSubjectArea
and 12
SubjectAreaName
AnswerChoice
the flight by the most direct route to the fix specified in the last clearance.
Answer A is incorrect because the winds at 2,000 feet and the surface winds do not flow in the same direction, but it is true that surface winds are weaker. Answer C is incorrect because winds aloft veer to the right, not the surface winds.
Answers A and B are incorrect because the range is between 10
and 12
Answer A is incorrect because the reaction force described in Newton's third law, for every action there is an equal and opposite reaction is known as centrifugal force. Answer B is incorrect because pressure gradient tends to cause the wind to flow perpendicular to the isobars.
Squawk 7600. Since you have received an "expect approach clearance" for 1015, plan to begin your approach at 1015.
PWI02.mpg
PWI04.mpg
If the communications failure occurs during an IFR flight in VFR conditions, or if VFR conditions are encountered after the failure, the pilot shall continue the flight under VFR and land as soon as practicable. If the failure occurs under IFR conditions you would continue the flight at the assigned altitude and route and complete the approach. FAR 91.185.
The surface winds tend to veer to the right of the winds at 2,000 feet and are usually weaker.
Which procedure should you follow if, during an IFR flight in VFR conditions, you have two way radio communications failure?
The greater density of the air at the surface.
and 10
questionsPerSection
correctAns
When using VOR for navigation, which of the following should be considered as station passage?
Squawk 7600; plan to begin your approach at 1015.
lessonsPerSection
PWI08.mpg
What causes surface winds to flow across the isobars at an angle rather than parallel to the isobars?
FigNumber
Answer B is incorrect because continued flight at the assigned altitude may take you back into IFR conditions. Answer C is incorrect because it is not required to land at the nearest airport that has VFR conditions.
Answer A is incorrect because Coriolis force deflects the winds aloft so that they rotate clockwise around a high pressure system and counterclockwise around a low pressure system. The winds aloft move parallel to the isobars. Answer C is incorrect because greater density of the air at the surface does not influence whether surface winds will or will not flow across the isobars at an angle rather than parallel to the isobars.
Answer A is correct.
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The winds at 2,000 feet tend to parallel the isobars while the surface winds cross the isobars at an angle toward lower pressure and are weaker.
PWI07.mpg
Coriolis.
A VOR receiver with normal five-dot course sensitivity shows a three-dot deflection at 30 NM from the station. The aircraft would be displaced approximately how far from the course centerline?
If the failure occurs in VFR conditions, or if VFR conditions are encountered after the failure, the pilot shall continue the flight under VFR, if possible, and land as soon as practicable. FAR 91.185.
Answer A is incorrect because if failure occurs in IFR conditions the pilot would continue on the route assigned in the last ATC clearance. Answer C is incorrect because the most direct route to the next fix may be through a mountain or restricted area.
Answers A and B are incorrect because neither the first movement of the CDI nor the TO-FROM indicator becoming blank as the VOR is approached is considered station passage.
Continue the flight under VFR and land as soon as practicable.
Pressure gradient.
QuestName
The winds at 2,000 feet and the surface winds flow in the same direction, but the surface winds are weaker due to friction.
Coriolis force.
(Refer to figure 87.) While holding at the 10 DME fix east of LCH for an ILS approach to RWY 15 at Lake Charles Regional airport, ATC advises you to expect clearance for the approach at 1015. At 1000 you experience two-way radio communications failure. Which procedure should be followed?
Squawk 7700 for 1 minute, then 7600. After 1 minute, descend to the minimum final approach fix altitude. Start your approach at 1015.
Coriolis force affects the paths of aircraft, ocean currents, and most important to the study of weather, air currents. Coriolis force deflects wind to the right in the Northern Hemisphere until the wind becomes parallel to the isobars.
The first positive, complete reversal of the TO FROM indicator.
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A full-scale 5-dot deflection would also be a 10
course change. A 3-dot deflection would be a 6
course change. If you are 60 NM from a VOR, 1
deflection equals one mile off course, or 6
deflection would be 6 miles off course. If you are only 30 NM from the VOR (half of 60 NM), then 6
of deflection would be half of 6 miles, or 3 NM off centerline.
Answers A and C are incorrect but could be obtained through faulty analysis or calculation.
When checking the sensitivity of a VOR receiver, the number of degrees in course change as the OBS is rotated to move the CDI from center to the last dot on either side should be between
cdNumber
In the event of two-way radio communications failure while operating on an IFR clearance in VFR conditions the pilot should continue
5 NM.
Answer B is correct.
by the route assigned in the last ATC clearance received.
Commclse.mpg
Squawk 7600 and listen on the LOM frequency for instructions from ATC. If no instructions are received, start your approach at 1015.
Centrifugal.
Surface friction.
2 NM.
PWI01.mpg
What relationship exists between the winds at 2,000 feet above the surface and the surface winds?
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